if you print the values of a, b ,c that satisfy and don't satisfy the
condiction cm == 50 at the same time, you can't know what works and
what did not work.
here is the code that i wrote and worked well
for a in range(1, 11): # i replaced 10 by 11 to include the 10
for b in range(1, 6): # same as before put 6 to include 5
for c in range(1, 6):
mc = (6*a) + (9*b) + (20*a)
if mc == 50:
print(a, b, c)
notice that i am using python 3.5, range is a generator like xrange in
python 2
and the result is 2 for a and b and 1 for c
I wish this coold help you
for what you said, here is the hard coded solution:
for a in range(1, 11):
for b in range(1, 6):
for c in range(1, 6):
mc = 6*a + 9*b + 20*c
if mc == 50:
print('for 50 McNuggets, "a"= {}, "b"={}, "c"={}'.format(a, b,
c))
if mc == 51:
print('for 51 McNuggets, "a"= {}, "b"={}, "c"={}'.format(a, b,
c))
if mc == 52:
print('for 52 McNuggets, "a"= {}, "b"={}, "c"={}'.format(a, b,
c))
if mc == 53:
print('for 53 McNuggets, "a"= {}, "b"={}, "c"={}'.format(a, b,
c))
if mc == 54:
print('for 54 McNuggets, "a"= {}, "b"={}, "c"={}'.format(a, b,
c))
if mc == 55:
print('for 55 McNuggets, "a"= {}, "b"={}, "c"={}'.format(a, b,
c))
and the result was
for 55 McNuggets, "a"= 1, "b"=1, "c"=2
for 53 McNuggets, "a"= 1, "b"=3, "c"=1
for 50 McNuggets, "a"= 2, "b"=2, "c"=1
for 53 McNuggets, "a"= 4, "b"=1, "c"=1
Or you can write a more elegant one:
for a in range(1, 11):
for b in range(1, 6):
for c in range(1, 6):
mc = 6*a + 9*b + 20*c
if mc in range(50, 56):
print('for {} McNuggets, "a"= {}, "b"={}, "c"={}'.format(mc,
a, b, c))
i used range(50, 56) to include the value 56
know , i wanted to know the purpose of this code:
> a=+1
> b=b+1
> c=c+1
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