The following code should do.
for a in range(1,10):
for b in range(1,5):
for c in range(1,5):
for mc in range(50, 55):
if mc ==(6*a)+(9*b)+(20*c):
print "mc= ",mc,"a= ",a,"b= ",b,"c=",c
regards,
Sarma.
On Mon, Aug 29, 2016 at 3:34 PM, Alan Gauld via Tutor <tutor@python.org> wrote:
> On 28/08/16 23:53, shahan khan wrote:
>>
>> I changed the code a bit and this is the result:
>> for a in range(1,11):
>> for b in range(1,6):
>> for c in range(1,6):
>> mc=(6*a)+(9*b)+(20*c)
>> if mc==50:
>> print 'For 50 McNuggets:''a=',a,'b=',b,'c=',c
>> if mc==51:
>> print 'Fpr 51 McNuggets:''a=',a,'b=',b,'c=',c
>> if mc==52:
>> print 'For 52 McNuggets:''a=',a,'b=',b,'c=',c
>> if mc==53:
>> print 'For 53 McNuggets:''a=',a,'b=',b,'c=',c
>> if mc==54:
>> print 'For 54 McNuggets:''a=',a,'b=',b,'c=',c
>> if mc==55:
>> print 'For 55 McNuggets:''a=',a,'b=',b,'c=',c
>> Result:
>> For 55 McNuggets:a= 1 b= 1 c= 2
>> For 53 McNuggets:a= 1 b= 3 c= 1
>> For 50 McNuggets:a= 2 b= 2 c= 1
>> For 53 McNuggets:a= 4 b= 1 c= 1
>>
>> Two questions:
>> 1) why is it printing backwards?
>
>
> It is printing in the order it finds them based on your loop values.
> So the first two have a=1, the 3rd has a=2 and the last a=4
>
> But please post in plain text not HTML since otherwise your code
> format gets messed up.
>
> Alan G
>
>
>
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