On Sat, Mar 25, 2017 at 3:31 PM, Peter O'Doherty wrote: > > def myFunc(num): > for i in range(num): > print(i) > > print(myFunc(4)) > 0 > 1 > 2 > 3 > None #why None here? > > Because there are two print() functions, one inside the function and another outside. When a function does not return anything, an implicit “return None” statement gets added to the end of the function.
The inner myFunc(4) is printing out 0, 1, 2, 3 and it also returns None which gets printed by the outer print() function. > > def myFunc(num): > for i in range(num): > return i > > print(myFunc(4)) > 0 #why just 0? The return statement causes the loop to stop and the function to exit and returns 0 to its caller which is the outer print() function. Hope that helps. Sri > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > https://mail.python.org/mailman/listinfo/tutor > _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
