In the following the function, x is reachable outside the scope of foo function.
In [1]: x = 10
In [2]: def foo():
...: return x
...:
In [3]: print(foo())
10
But why it is not the case when the look up happens inside a instance method of
a class?
In [1]: class Foo:
...: x = 10
...: def bar(self):
...: return x
...:
In [2]: Foo().bar()
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
<ipython-input-2-77cc08b8637b> in <module>
----> 1 Foo().bar()
<ipython-input-1-202509464a3d> in bar(self)
2 x = 10
3 def bar(self):
----> 4 return x
NameError: name 'x' is not defined
I figured I have to access it like:
In [1]: class Foo:
...: x = 10
...: def bar(self):
...: return self.__class__.x
...:
...: print(Foo().bar())
10
Just want to know how these search happens in 2 contexts.
Thanks,
Arup Rakshit
a...@zeit.io
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