I have read that document. Like I said in my initial post - I have read the tutorials and FAQs.
Furthermore - I have converted a C# Class that utilises OAuth C# Base Class to VB.NET without a hitch. It works just fine - the only problem is that it is reaching a Login prompt that is asking for credentials that I do not have. A. Williams - did you even read my last post? I find it highly ignorant of you to refer me to the guide when I have successfully authenticated the OAuth procedure. That said, will anyone who cares to read my posts reply with some thing that is relevant and makes sense? I have given all the URL's needed - the parameters I am passing to Twitters oauth page - and I am getting a LOGIN PROMPT. Read my previous posts for more information. Kind regards, Obrzut On Jun 25, 7:23 pm, Abraham Williams <4bra...@gmail.com> wrote: > I would recommend readinghttp://oauth.net/documentation/getting-startedso you > have a thorough > understanding of how Oauth. > > > > > > On Thu, Jun 25, 2009 at 12:17, Obrzut<sa...@peyoteuk.com> wrote: > > > WOW! Thanks! I'll try that! > > > Just a side note - I extracted the URL and ran it thru a web browser - > > then it started popping open a Username / Password box? > > > It stated; > > > The server twitter.com at Twitter API requires a username and > > password. > > > What is all this about? I ask, because, my twitter username and > > password do not work? > > > When I ran the URL via the web browser object in VB.NET the document > > completed without any body of text. It just exited without a login > > prompt. Nothing. > > > So, it seems the URL I am creating seems sound - as it created a Login > > prompt in google Chrome. But, I dunno what credentials I require for > > the login prompt? > > >http://twitter.com/oauth/access_token?oauth_version=1.0&oauth_nonce=2... > > > This is the URL I used to access the login prompt. > > > Any pointers? > > > On Jun 25, 6:04 pm, Bojan Rajkovic <boj...@brandeis.edu> wrote: > >> -----BEGIN PGP SIGNED MESSAGE----- > >> Hash: SHA1 > > >> Obrzut wrote: > >> > "oauth_version=1.0&oauth_nonce=5048009&oauth_timestamp=1245948327&oauth_sig > >> > nature_method=HMAC- > >> > SHA1&oauth_consumer_key=CgZiTeNqGk2c0eZSdb9qg&oauth_signature=vxFWk3JvGKdKI > >> > RYR31%2b2JC > >> > %2bh30o%3d" > > >> > This is an example URL I am sending. Is there anything suspect you can > >> > see just by looking at it? > > >> > It really would help me out no end. > > >> > Kind regards, > > >> > Obrzut > > >> You need to apply a lexicographical byte ordering to the OAuth > >> parameters--that is, sort them alphabetically. > > >> I ran into this in the beginning, and scratched my head for a while > >> until I read the OAuth standard. > > >> Cheers, > > >> - -- > >> Bojan Rajkovic <boj...@brandeis.edu> > >> Biochemistry '10, Brandeis University > >> PGP Signature Key ID: 0x8783D016 > >> PGP Encryption Key ID: 0x2497B8B2 > >> -----BEGIN PGP SIGNATURE----- > >> Version: GnuPG v1.4.9 (GNU/Linux) > >> Comment: Using GnuPG with Mozilla -http://enigmail.mozdev.org > > >> iQIcBAEBAgAGBQJKQ647AAoJEO4IwQyHg9AWnVkP/2H5dQWnGSYXGGQV0YW6oswQ > >> gBELIhWjHiq9lkQQbOrCUqV6hR4wycSa5hNfaW+YxQsVEuORTw1FAhiayJPRcVAH > >> I8cgewOSgXG5CSbXfutPmfQFHZNdN3zgJMaS0sAwoyEik+nb/JePlUEkn7f9CPzb > >> buqLAjadh0bLNdB/U2ld5FBgnAc1zQEJrGCePqfzYls3RTQm+dc6wtpzRnlKVDER > >> hfsVh0E9OUZOIjEmaHsc7KUjoiATSB/j0LXrF+3x3BR/ISYkoLW0cJPQEscJVrG+ > >> JbtJ3Q4H1uJpDn5iF4ENhzjZa1/v45w/zliXk8MeDixLC4jtTUE54oKZsYFjhL/v > >> d1BMgmgTVCJq7Qj2jJNKjD/A2nriAErh/i/42850MsF9JCnff6d2kruXccdHM8Lv > >> ExttUH9k6c0U4SBVYjjv+Np4OOwWDJvwNx3mXW5mgfLsCtMKdSDD+mm4/M9MHDxR > >> sHo54jlWDXGYHrbAJLtCBp02UN3FTlieQ61QYniaUJcZOuzMoKkmVn4/uHMJT7SQ > >> u+DxUMYaFEpot72IOzgFmAmeToGw1GWyeBzeZnkPq5li5Y+EyUCVKH8dxSj4omM+ > >> qUHwvhI93cS6+mmh3L1KGsfg6uXl88xi1oP3d+k1N65nX4troGWE00VPROTbAPzk > >> +UNJsrk9WkRuaif1le0b > >> =M/IL > >> -----END PGP SIGNATURE----- > > -- > Abraham Williams | Community Evangelist |http://web608.org > Hacker |http://abrah.am|http://twitter.com/abraham > Project |http://fireeagle.labs.poseurtech.com > This email is: [ ] blogable [x] ask first [ ] private.
