Dear Reinhard Meyer,

In message <4cc66a67.4000...@emk-elektronik.de> you wrote:
>
> > It fails in case the timer wraps around.
> >
> > Assume 32 bit counters, start time = 0xFFFFFFF0, delay = 0x20. It
> > will compute end = 0x10, the while codition is immediately false, and
> > you don't have any delay at all, which most probably generates a
> > false error condition.
> 
> I used and assumed a 64 bit counter, that will not wrap around while
> our civilization still exists...


The code is still wrong, and as a simple correct implementation exists
there is no excuse for using such incorrect code.

Please fix that!

> If get_ticks() is only 32 bits worth, both methods will misbehave
> at a 32 bit wrap over.

No.

> >     start = time();
> >     while ((time() - start)<  delay)
> >             ...
> >
> > This works much better (assuming unsigned arithmetics).
> 
> True, provided the underlying timer is really 64 bits, otherwise
> this fails, too...

You are wrong. Try for example this:

--------------------- snip -------------------
#include <stdio.h>

int main(void)
{
        unsigned int time = 0xFFFFFFF0;
        unsigned int delay = 0x20;
        unsigned int start;

        start = time;

        printf("start=0x%X\n", start);

        while ((time - start) < delay) {
                printf("time=0x%X...\n", time);
                ++time;
        }

        return 0;
}
--------------------- snip -------------------

> Best would be to assign get_ticks() to a 32 bit unsigned and use
> 32 bit vars for start and delay as well.

? But that's what I wrote?

Best regards,

Wolfgang Denk

-- 
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