result:=[]
every ti:=!X.member_of do
put(result, something)
is possible (thanks to Steve Hunter) with every put(result:=[],something(!X.member_of))
That surprised me, because I thought that every resumes whole expression. Is it possible to do it more generally?
result1:=[]
result2:=[]
every ti:=!X.member_of do
{ put(result1, something1(ti))
put(result2, something2(ti))
}----
Kazimir Majorinc, Zagreb, Croatia
