I am not an expert in regex or filtering by any means so Quentin’s message
prompted me to take a closer look. I started with the dictionary entry for
filter and I found this simple example:
filter items of "apple,banana,cherry" with regex pattern "b.*"
Since we are not specifying a destination, the result is going into the “it"
variable. I tried that and got the expected result “banana”. Next I tried “c.*”
and got cherry and “d.*’ and got nothing. All good. Finally I tried “a.*” and
got “apple, banana”. I was a bit surprised by that. Does anyone know why “a.*”
breaks the pattern of returning a single item? Does it have something to do
with the item being in the first position in the string?
BTW, I did try putting the result into a variable and displaying that (… into
temp; put temp) and got the same result.
Also, I thought I might try a few experiments using “without regex pattern” and
using “a.*” as the argument returned “cherry” so at least whatever it is doing
it is consistent.
Mark
> On Mar 7, 2022, at 8:58 AM, Quentin Long via use-livecode
> <use-livecode@lists.runrev.com> wrote:
>
> sez j. landman gay:
>> Interesting idea. There are 25 letters on each board, some are always
>> repeats. I think I'd need
>> a good regex so I wouldn't have to run the filter command multiple times.
>> How's your regex?
>
> I see you've already implemented something, but just for grins, here's my
> thought re: the One True Regex for this situation:
> AbsentChars is the name of a variable which contains all the letters that
> *aren't* on the board. My first attempt at the regex is…
> filter lines of WordList without "*[AbsentChars]*"
> However, that will remove all words that contain at least one letter in the
> specific character string "absentchars", which is not what I want. So, bring
> out the "do" keyword…
> do ("filter lines of WordList without" && quote & "*" & AbsentChars & "*" &
> quote)
>
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