On 17 Jun 2008, at 23:57, Richard Gaskin wrote:
But I guess I'm stuck on the old (outdated?) notion that functions
are evaluated before their result is used in the calling command,
which would mean the calling sort command is effectively using:
sort lines of fld 1 by 1
Except that though we don't know exactly what the engine is doing,
it's probably computing the value of the sort expression for each
line and then doing the sort.
Best,
Mark
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