Malte,
One caveat. The algorithm in my previous message assumes the polygon is simply connected--all points accessible without crossing the boundary. It calculates the area of a polygon transversed in the counter-clockwise sense as positive, and negative if transversed in the clockwise sense. Thus the area of a symmetric figure eight-like polygon would be zero.
But this complication can be overcome if it is an issue.
Jim _______________________________________________ use-revolution mailing list [EMAIL PROTECTED] http://lists.runrev.com/mailman/listinfo/use-revolution
