Scott,
That's right. You double-click a file in Windows and Windows starts
another instance of the executable for that file. In that executable,
you catch the relaunch message. If file $1 exists, don't return any
value from the relaunch handler. The new instance will be terminated
and the message is passed on to the already running instance.
Note that the message is sent to the already running instance. The
already running instance decides whether the new instance of the
executable is to be terminated or not.
--
Best regards,
Mark Schonewille
Economy-x-Talk Consulting and Software Engineering
Homepage: http://economy-x-talk.com
Twitter: http://twitter.com/xtalkprogrammer
Buy flowers for your Valentine and get the computer game TwistAWord
for free. Visit http://www.twistaword.net or http://qurl.tk/4h
Op 13 feb 2010, om 22:15 heeft Scott Rossi het volgende geschreven:
Recently, Mark Schonewille wrote:
There are several intresting posts about this subject in the archives
of this list. On of them can be found here http://qurl.tk/4x You
probably have that info already, since it is Ken's.
Thanks Mark. The one (?) item I'm unclear on is the script example:
on openStack
put $0 into theAppPath
put $1 into theDocToOpen
answer "The doc to open is: " & theDocToOpen
end openStack
Wouldn't this execute only when the app is first launched? What
message is
sent to the app while the app is running? Or am I just not
understanding
the way this works?
Thanks & Regards,
Scott Rossi
Creative Director
Tactile Media, UX Design
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