On Thursday, February 12, 2004, at 03:14 PM, Thomas McGrath III wrote:
Mark,
Wow, this is more than I expected. Thank you.
These functions seem to be the ticket for me. I will play with them and try to understand them and report back.
Thanks again,
Tom
You're welcome.
If you have troubles determining how many paragraphs there are in a paragraph array then try this:
-----------------------
put 1 into countNum
repeat
put theParagraphArray[countNum] into zap
if zap = empty then
put (countNum - 1) into timesP
exit repeat
end if
add 1 to countNum
end repeat
-- timesP now contains the number of <p>...</p> sets that where found.
-----------------------
Mark
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