No, the schema needs to be present in some form to tell the reader how to
decode the data.
You can generate classes from the schema and pass in the class, but that is
just a different way of passing in the schema.
On Mon, Dec 5, 2011 at 9:33 AM, Gaurav <gaurav...@gmail.com> wrote:
> Hi,
>
> I am trying to read byte stream of encoded data, which is coming from some
> source but File. So I should not use DataFileReader.
>
> I wrote following code to do that, but here I have to specify schema on my
> own, which ideally should come from data itself. Is there any other way to
> get decode data with explicitly specifying schema and without using
> DataFileReader?
> ----------------------
> private static void DecodeData(byte[] buf) throws IOException {
> // TODO Auto-generated method stub
> Schema schema = createSchema();
> GenericDatumReader<GenericData.Record> datum = new
> GenericDatumReader<GenericData.Record>(schema);
>
> ByteArrayInputStream in = new ByteArrayInputStream(buf);
> BinaryDecoder decoder = DECODER_FACTORY.binaryDecoder(in,
> null);
>
> GenericData.Record record = new
> GenericData.Record(datum.getSchema());
> datum.read(record, decoder);
>
> System.out.println(record.get("trade"));
> }
> ---------------------
>
> Thanks,
> Gaurav Nanda
>
> --
> View this message in context:
> http://apache-avro.679487.n3.nabble.com/Decode-without-using-DataFileReader-tp3561722p3561722.html
> Sent from the Avro - Users mailing list archive at Nabble.com.
>
--
Matt Stevenson.
