There is no one currently slated to volunteer to RM the release. Good time to ask though!
Do have a committer here willing to volunteer to release Commons CSV 1.5? Thank you, Gary On Fri, Aug 11, 2017 at 3:27 PM, nitin mahendru <nitin.mahendr...@gmail.com> wrote: > Thanks for accepting the pull request. > Any pointers on when the version 1.5 will be released ? > > > > > On Thu, Aug 10, 2017 at 2:19 PM nitin mahendru <nitin.mahendr...@gmail.com > > > wrote: > > > Thanks Greg. > > Well the problem actually was that I am behind a proxy. So my mistake. > > Sorry for that. > > > > I have raised a pull request and a JIRA item CSV-214. Looking forward to > > your feedback. > > > > Thanks > > > > Nitin > > > > > > > > > > On Thu, Aug 10, 2017 at 1:08 PM Gary Gregory <garydgreg...@gmail.com> > > wrote: > > > >> Use the button provided by GitHub to copy the repo URL to the clipboard, > >> then you can just use "git clone <PASTE>" > >> > >> On Thu, Aug 10, 2017 at 1:05 PM, nitin mahendru < > >> nitin.mahendr...@gmail.com> > >> wrote: > >> > >> > Hello All, > >> > > >> > I raised a JIRA ticket(CSV-214) to make some changes to the code for > >> what I > >> > a trying to do. The description on the ticket might help explain > things > >> > better. Now I am trying to clone the repo to make a pull request but I > >> am > >> > just stuck at this: > >> > > >> > git -c http.sslVerify=false clone https://github.com/apache/ > >> > commons-csv.git > >> > Cloning into 'commons-csv'... > >> > fatal: https://github.com/apache/commons-csv.git/info/refs not valid: > >> is > >> > this a git repository? > >> > > >> > > >> > Any Idea about this ? > >> > > >> > Thanks > >> > > >> > Nitin > >> > > >> > > >> > > >> > > >> > > >> > On Wed, Aug 9, 2017 at 5:17 PM Gary Gregory <garydgreg...@gmail.com> > >> > wrote: > >> > > >> > > On Wed, Aug 9, 2017 at 5:04 PM, Guang Chao < > guang.chao.1...@gmail.com > >> > > >> > > wrote: > >> > > > >> > > > On Wed, Aug 9, 2017 at 6:12 AM, nitin mahendru < > >> > > nitin.mahendr...@gmail.com > >> > > > > > >> > > > wrote: > >> > > > > >> > > > > Hello All, > >> > > > > > >> > > > > I am trying to read in a csv file which may be 'crlf' or 'lf' > >> > > seperated. > >> > > > > Then I want to change a particular column, say encrypt it and > then > >> > > write > >> > > > > back a new csv with that updated column. I want to use the same > >> > record > >> > > > > separator as was in the input file. > >> > > > > > >> > > > > Is there a way to get the record separator back from the > CSVParser > >> > > > object ? > >> > > > > I am planning to use the below method to get the writer. > >> > > > > CSVFormat.RFC4180.withRecordSeparator(<need to add record > >> > > > > separator).print() > >> > > > > > >> > > > > For using the above I need to know the record separator upfront > >> > which I > >> > > > > have no clue about as the Parser object does not expose that > >> detail. > >> > > > > > >> > > > > thanks > >> > > > > > >> > > > > Nitin > >> > > > > > >> > > > > >> > > > I think CSVParser is strict and may not work for both LF and CRLF. > >> > Maybe > >> > > > try to scan the file first and see if line ending is lf or crlf, > and > >> > then > >> > > > use a corresponding CSVParser instance that can handle each case. > >> > > > > >> > > > >> > > That's not how it works now but feel free to provide a PR on GitHub > >> ;-) > >> > > > >> > > Gary > >> > > > >> > > > > >> > > > -- > >> > > > Guang <http://javadevnotes.com/java-string-split-newline-examples > > > >> > > > > >> > > > >> > > >> > > >
