Hey, > outE/outV # confusing way of saying (in XPath) "self::node()" > inE/inV # ditto
.I suppose----but once you get to an edge, you need to specify where you want to go next (the tail or the head of the edge).. ? The outE/V convention would mean you have to know that you did outE the prior step to infer you mean the head of the edge at the next step... no? If you really care, you can define a path: path forward ./outE/inV end path backward ./inE/outV end Then you can do: ./forward/forward/forward :). See ya, Marko. _______________________________________________ Neo mailing list User@lists.neo4j.org https://lists.neo4j.org/mailman/listinfo/user