Hi,
Scenario 1:
I would like to get all Nodes that do not have a relationship to another node.
What is the best way to do this Gremlin?
Root => NodeA => NodeB
Root => NodeC
Output should be NodeC
Scenario 2:
Root = > User -> Centre
I would like to get all centres for userA, and then get all users who are also
linked to the same centres of the userA
Scenario 3:
User => Centre
I would like to get all users that do not have a link to a Centre, and if this
is the case, do a projection that returns a fake centre with property "Unknown"
Scenario 4:
REFERRAL => PERSON
I would like to combine a query that gets all
Referrals that are linked to a person and project a table result (contains
referrals and person property values (this is easy to do)
However, I then want to do a SPLIT query, that gets referrals without the
persons, and then MERGE both back into the table projection? So table projecton
might look like this.
I guess this is done with .table().it{}....cap, but what I am not sure, is how
to do a split and merge in parallel and then get that merge projected into the
same table.
ReferralId, Name
1, Bob
2, Jill
3, null
4, null
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