Hi, Will the below mentioned snippet work for Spark 1.4.0 Thanks for your inputs
Regards, Satish -----Original Message----- From: "Yanbo Liang" <yblia...@gmail.com> Sent: 12-12-2015 20:54 To: "satish chandra j" <jsatishchan...@gmail.com> Cc: "user" <user@spark.apache.org> Subject: Re: Concatenate a string to a Column of type string in DataFrame Hi Satish, You can refer the following code snippet: df.select(concat(col("String_Column"), lit("00:00:000"))) Yanbo 2015-12-12 16:01 GMT+08:00 satish chandra j <jsatishchan...@gmail.com>: HI, I am trying to update a column value in DataFrame, incrementing a column of integer data type than the below code works val new_df=old_df.select(df("Int_Column")+10) If I implement the similar approach for appending a string to a column of string datatype as below than it does not error out but returns only "null" values val new_df=old_df.select(df("String_Column")+"00:00:000") OR val dt ="00:00:000" val new_df=old_df.select(df("String_Column")+toString(dt)) Please suggest if any approach to update a column value of datatype String Ex: Column value consist '20-10-2015' post updating it should have '20-10-201500:00:000' Note: Transformation such that new DataFrame has to becreated from old DataFrame Regards, Satish Chandra