Sorry, it was added since 1.5.0.
2015-12-13 2:07 GMT+08:00 Satish <jsatishchan...@gmail.com>:
> Hi,
> Will the below mentioned snippet work for Spark 1.4.0
>
> Thanks for your inputs
>
> Regards,
> Satish
> ------------------------------
> From: Yanbo Liang <yblia...@gmail.com>
> Sent: 12-12-2015 20:54
> To: satish chandra j <jsatishchan...@gmail.com>
> Cc: user <user@spark.apache.org>
> Subject: Re: Concatenate a string to a Column of type string in DataFrame
>
> Hi Satish,
>
> You can refer the following code snippet:
> df.select(concat(col("String_Column"), lit("00:00:000")))
>
> Yanbo
>
> 2015-12-12 16:01 GMT+08:00 satish chandra j <jsatishchan...@gmail.com>:
>
>> HI,
>> I am trying to update a column value in DataFrame, incrementing a column
>> of integer data type than the below code works
>>
>> val new_df=old_df.select(df("Int_Column")+10)
>>
>> If I implement the similar approach for appending a string to a column of
>> string datatype as below than it does not error out but returns only
>> "null" values
>>
>> val new_df=old_df.select(df("String_Column")+"00:00:000")
>> OR
>> val dt ="00:00:000"
>> val new_df=old_df.select(df("String_Column")+toString(dt))
>>
>> Please suggest if any approach to update a column value of datatype String
>> Ex: Column value consist '20-10-2015' post updating it should have
>> '20-10-201500:00:000'
>>
>> Note: Transformation such that new DataFrame has to becreated from old
>> DataFrame
>>
>> Regards,
>> Satish Chandra
>>
>>
>>
>>
>
>
