Thank you sir.
Can one do this sorting without using temporary table if possible?
Best
On Saturday, 27 February 2016, 18:50, Yin Yang <yy201...@gmail.com> wrote:
scala> Seq((1, "b", "test"), (2, "a", "foo")).toDF("id", "a",
"b").registerTempTable("test")
scala> val df = sql("SELECT struct(id, b, a) from test order by b")df:
org.apache.spark.sql.DataFrame = [struct(id, b, a): struct<id: int, b: string
... 1 more field>]
scala> df.show+----------------+|struct(id, b, a)|+----------------+|
[2,foo,a]|| [1,test,b]|+----------------+
On Sat, Feb 27, 2016 at 10:25 AM, Ashok Kumar <ashok34...@yahoo.com.invalid>
wrote:
Hello,
I like to be able to solve this using arrays.
I have two dimensional array of (String,Int) with 5 entries say arr("A",20),
arr("B",13), arr("C", 18), arr("D",10), arr("E",19)
I like to write a small code to order these in the order of highest Int column
so I will have arr("A",20), arr("E",19), arr("C",18) ....
What is the best way of doing this using arrays only?
Thanks
