Hello Yong, First of all, thank your attention. Note that the values of elements, which have values at RDD/DF1, in the same list will be always same. Therefore, the "1" and "3", which from RDD/DF 1, will always have the same value which is "a".
The goal here is assigning same value to elements of the list which does not exist in RDD/DF 1. So, all the elements in the same list can have same value. Or, the final RDD/DF also can be like this, [1, 2, 3], a [4, 5], b Thank you again. - Mungeol On Wed, Mar 29, 2017 at 9:03 PM, Yong Zhang <[email protected]> wrote: > What is the desired result for > > > RDD/DF 1 > > 1, a > 3, c > 5, b > > RDD/DF 2 > > [1, 2, 3] > [4, 5] > > > Yong > > ________________________________ > From: Mungeol Heo <[email protected]> > Sent: Wednesday, March 29, 2017 5:37 AM > To: [email protected] > Subject: Need help for RDD/DF transformation. > > Hello, > > Suppose, I have two RDD or data frame like addressed below. > > RDD/DF 1 > > 1, a > 3, a > 5, b > > RDD/DF 2 > > [1, 2, 3] > [4, 5] > > I need to create a new RDD/DF like below from RDD/DF 1 and 2. > > 1, a > 2, a > 3, a > 4, b > 5, b > > Is there an efficient way to do this? > Any help will be great. > > Thank you. > > --------------------------------------------------------------------- > To unsubscribe e-mail: [email protected] > --------------------------------------------------------------------- To unsubscribe e-mail: [email protected]
