Is it possible for one key in 2 groups in rdd2?

[1,2,3]
[1,4,5]

?

On Thu, 30 Mar 2017 at 12:23 pm, Mungeol Heo <mungeol....@gmail.com> wrote:

> Hello Yong,
>
> First of all, thank your attention.
> Note that the values of elements, which have values at RDD/DF1, in the
> same list will be always same.
> Therefore, the "1" and "3", which from RDD/DF 1, will always have the
> same value which is "a".
>
> The goal here is assigning same value to elements of the list which
> does not exist in RDD/DF 1.
> So, all the elements in the same list can have same value.
>
> Or, the final RDD/DF also can be like this,
>
> [1, 2, 3], a
> [4, 5], b
>
> Thank you again.
>
> - Mungeol
>
>
> On Wed, Mar 29, 2017 at 9:03 PM, Yong Zhang <java8...@hotmail.com> wrote:
> > What is the desired result for
> >
> >
> > RDD/DF 1
> >
> > 1, a
> > 3, c
> > 5, b
> >
> > RDD/DF 2
> >
> > [1, 2, 3]
> > [4, 5]
> >
> >
> > Yong
> >
> > ________________________________
> > From: Mungeol Heo <mungeol....@gmail.com>
> > Sent: Wednesday, March 29, 2017 5:37 AM
> > To: user@spark.apache.org
> > Subject: Need help for RDD/DF transformation.
> >
> > Hello,
> >
> > Suppose, I have two RDD or data frame like addressed below.
> >
> > RDD/DF 1
> >
> > 1, a
> > 3, a
> > 5, b
> >
> > RDD/DF 2
> >
> > [1, 2, 3]
> > [4, 5]
> >
> > I need to create a new RDD/DF like below from RDD/DF 1 and 2.
> >
> > 1, a
> > 2, a
> > 3, a
> > 4, b
> > 5, b
> >
> > Is there an efficient way to do this?
> > Any help will be great.
> >
> > Thank you.
> >
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> >
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> --
Best Regards,
Ayan Guha

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