What?
I'm sorry, but I'm not asking about how to assemble an URL.
I want to retrieve the original URL sent by the browser in the request.
The request.getRequestURL() is wrapped and modified with each forward,
and I want the first, by the browser, requested URL.
Since so many seem to misunderstand me:
1. User inputs "http://localhost/appname/input.do"; in browser. (Mapped
to InputAction)
2. InputAction's request.getRequestURL() is
"http://localhost/appname/input.do";
3. InputAction forward to OtherAction.
4. The OtherAction's request.getRequestURL() is
"http://localhost/appname/other.do";. <-- THIS ISN'T WHAT I WANT.
I want to retrieve the URL "http://localhost/appname/input.do"; in the
OtherAction WITHOUT modifying InputAction. How do I do this?
Rimzim Sinha skrev:
Try
getContextPAth + gathRequestURL...
Martin Gainty <[EMAIL PROTECTED]> wrote:
http://www.docjar.com/docs/api/org/apache/struts/action/Action.html#execute(org.apache.struts.action.ActionMapping,%20org.apache.struts.action.ActionForm,%20javax.servlet.http.HttpServletRequest,%20javax.servlet.http.HttpServletResponse)
The second parameter of the Action execute method is 'ActionForm'
HTH,
Martin-
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----- Original Message -----
From: "David Grundberg"
To: "Struts Users Mailing List"
Sent: Sunday, September 10, 2006 8:46 AM
Subject: How do I get the original RequestURI?
Hi,
I want to do something like this:
1. User enters http://localhost/appname/welcome.do
2. PlaceAction forwards to list.do
3. In ListAction, I want to retrieve the URL the user entered
"/appname/welcome.do".
The problem: when I run getRequestURI in the ListAction, all I get is
"/appname/list.do". I guess this is a sort of natural thing for it to
do, but how do I get the original URI? (/appname/welcome.do)
Any help appreciated!
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