Jake Vang wrote:
>
>> If you want Spring to create your action class (as opposed to Struts
>> creating them) then you need to define your action in the
>> applicationContext.xml file.
>
> how do you do that? here's a couple of ways i have tried that do NOT work.
>
1) Add <constant name="struts.objectFactory"
value="org.apache.struts2.spring.StrutsSpringObjectFactory" /> to your
struts.xml file.
2) Add <listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
to your web.xml
3) Make sure that you have the Struts2 Spring plugin installed.
4) Put something along the lines of
<bean id="myAction" class="com.somwhere.mypackage.MyAction"
scope="prototype"/> (The scope prototype is important otherwise Spring
creates a singleton rather than a new action on each invocation which is
what Struts 2 expects)
and that should get Spring instantiating your action classes for you.
Although I'm guessing from your response you've already got to that stage.
I'm not sure that I understand what you are trying to acheive with
<bean name="/action" class="com.services.MyAction">
<property name="propertyA" value="${propertyA}"/>
</bean>
If you're trying to inject another class, then the format is on the lines of
<bean name="/action" class="com.services.MyAction">
<property name="classA" ref="classA"/>
</bean>
where you need a setter that matches the name parameter (setClassA(ClassA
classA)) in MyAction. The ref value points to another <bean id="classA"
class="com.services.classA"/>
HTH and I haven't completely misunderstood what you are trying to do.
Regards
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