Can we see the stack traces?

On 3/12/07, Fermin Da Costa Gomez <[EMAIL PROTECTED]> wrote:


> I haven't tried, but do you have problems with
> Class.forName(someRootAsString).newInstance() ?
Correct. Assuming i'm not making some very silly misstake

> The only thing I can think of that might cause problems would be in
> the lookup of the xsbs.
> Can you update teh list with what issues you have?
Here it goes:

<snip>
...
        // This bit works just fine so the class in itself is known
         FundDocument fundDoc=
FundDocument.Factory.newInstance();

         try {
             String clazz1 = "Fund"+ "DocumentImpl";
             Object xmlObject = Class.forName(clazz2).newInstance(); //
Returns a ClassNotFound Exception

            String clazz2 = "noNamespace."+ "Fund"+ "Document";
             Object xmlObject = Class.forName(clazz2).newInstance(); //
Returns an Instantiation Exception

        } catch (Exception e) {
            e.printStackTrace();
        }
 ...
</snip>


What i would like to so is use the xmlObject in a generic fashion so i don't
have to hardcode.

Is this enough info? If not please let me know.

Tia

Fermin
>
> > > I haven't seen a previous post on the list about this topic. That may
> > > be why you didn't get an answer :)
> > Hmm, that would explain it, indeed.
> >
> > What problems are you seeing when you try the code you list below?
> > >
> > > If I understand your problem correctly, you have something like:
> > > <el>1</el1> and you want to determine what type that is so you can
use
> > > somenamespace.ElDocument as your type. Is this correct?
> >
> > No exactly. I think i have to be more clear (always a challenge but here
it
> > goes .. )
> >
> > I'v got the big jar that is produced when you run scomp on an xsd.
> > When using the code in a normal fashion one would just get an object,
say
> > SomeRoot, and use the
SomeRootDocument.Factory.someMethod()
> > to accomplish whatever.
> >
> > Now, what i want to do is slightly different.
> > Rather than using SomeDocumentRootDocument explicitly i am looking for a
way
> > to use the
Class.forName(someRootAsString).newInstance()
> > method to get my hands on an xmlbeans document that i specify via a
string.
> > This way i don't have to hardcode the construction of the xml but i
could
> > supply the structure via simple strings, read via a small input file.
> > If this is possible one can construct any xml (sub)doc (based on the
overall
> > xsd) without having to code for it.
> >
> > Does this make sense?
> >
> > > Have you tried something like:
> > > XmlObject xo = XmlObject.Factory.parse("<el>1</el1>");
> > > and
> > > xo.type
> > > xo.type.getName
> > Since this suggests the string being an xml element i have not because i
> > would be looking for a className (the string thereof) to be handed of
and
> > return with an instance of type XmlObject.
> > Basically i don't know where the xml is going to start so i just want to
> > supply a string (name of the element to denote as root of the document
to be
> > build), create the corresponding document and build the rest of the
xml-doc
> > in the same fashion.
> >
> > > the scan the classes you expect to find a matching type
> > > if(ElDocument.type.getName == xo.type.getName){
> > >    // do something
> > > }
> > >
> > >
> > > -Jacobd
> > >
> > > On 3/12/07, Fermin Da Costa Gomez <[EMAIL PROTECTED] > wrote:
> > > > Hi,
> > > >
> > > > Just started on Xmlbeans and going through the list has not yielden
an
> > > > answer to my question.
> > > >
> > > > Is there a way to get a hold of a SomeDocument object by using
> > > > Class.forName("namespace.SomeDocument").newInstance() .. ?
> > > > Or any other way by means of just using a string that refers/ points
to
> > the
> > > > element one is looking for?
> > > >
> > > > So i have got the name of a document/ node/ tag in the form of a
string
> > and
> > > > i'm looking for an object based on that string.
> > > >
> > > > Tia,
> > > >
> > > > Fermin DCG
> > > >
> > > >
> > >
> > >
> >
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> > >
> > >
> >
> >
> >
> > --
> >  "The reasonable man adapts himself to the world; the unreasonable one
> > persists in trying to adapt the world to himself. Therefore all progress
> > depends on the unreasonable man."
> > - George Bernard Shaw (1856 - 1950)
>
>
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--
 "The reasonable man adapts himself to the world; the unreasonable one
persists in trying to adapt the world to himself. Therefore all progress
depends on the unreasonable man."
- George Bernard Shaw (1856 - 1950)

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