Pascal,
in
<a xmlns="mynamespace">
<b/>
</a>
what you have is every element within and including a being qualified as
having the namespace "mynamespace". Thus, the XPath must qualify the
elements too. This is only logical.
There are a couple of ways you can qualify the elements in the XPath.
You can use the prolog you have in
"declare namespace xs='mynamespace';/xs:a/xs:b"; you can also use
"declare default namespace 'mynamespace; /a/b".
The bottom line is that the path must follow the structure of the
document. If elements/attributes are namespace-qualified in the
document, then they must be too in the path.
- Wing Yew
________________________________
From: Pascal Maugeri [mailto:[EMAIL PROTECTED]
Sent: Friday, February 22, 2008 8:40 AM
To: [email protected]
Subject: Applying XPath to an XML with or without namespace
Hi
I would like to have some clarifications on how to apply XPath query on
a XML document depending if it comes with or without a namespace
definition.
When I run the following code executing the XPath query /a/b on a
document with no namespace:
String doc = "<a><b/></a>";
String query = "/a/b";
XmlObject xml = XmlObject.Factory.parse(doc);
XmlCursor cursor = xml.newCursor();
cursor.push();
cursor.selectPath(query);
it gives me the correct result (<c/>).
But if if the document comes with a namespace, for instance:
<a xmlns="mynamespace">
<b/>
</a>
the same code does not give me any result.
After investigating I found that a working code could be:
String doc = "<a xmlns="mynamespace"><b/></a>";
String query = "declare namespace xs='mynamespace';/xs:a/xs:b";
XmlObject xml = XmlObject.Factory.parse(doc);
XmlCursor cursor = xml.newCursor();
cursor.push();
cursor.selectPath(query);
Is there a better way to do this without having to set the prefix "xs:"
in the Xpath query for each level ? I would like to find a generic way
to handle XML documents with or without namespace.
Regards,
Pascal
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