Pascal, the xpath function "local-name()" is may the proper one for your purposes, take a look.
Regards, John On Fri, February 22, 2008 21:14, Wing Yew Poon wrote: > Sorry, typo - the query should have been "declare default element > namespace 'mynamespace'; /a/b". > > ________________________________ > > > From: Wing Yew Poon [mailto:[EMAIL PROTECTED] > Sent: Friday, February 22, 2008 11:11 AM > To: [email protected] > Subject: RE: Applying XPath to an XML with or without namespace > > > > Pascal, > in <a xmlns="mynamespace"> > <b/> > </a> > what you have is every element within and including a being qualified as > having the namespace "mynamespace". Thus, the XPath must qualify the > elements too. This is only logical. There are a couple of ways you can > qualify the elements in the XPath. You can use the prolog you have in > "declare namespace xs='mynamespace';/xs:a/xs:b"; you can also use > "declare default namespace 'mynamespace; /a/b". > The bottom line is that the path must follow the structure of the > document. If elements/attributes are namespace-qualified in the document, > then they must be too in the path. - Wing Yew > > > > ________________________________ > > > From: Pascal Maugeri [mailto:[EMAIL PROTECTED] > Sent: Friday, February 22, 2008 8:40 AM > To: [email protected] > Subject: Applying XPath to an XML with or without namespace > > > > Hi > > > I would like to have some clarifications on how to apply XPath query on > a XML document depending if it comes with or without a namespace > definition. > > When I run the following code executing the XPath query /a/b on a > document with no namespace: > > String doc = "<a><b/></a>"; > String query = "/a/b"; > XmlObject xml = XmlObject.Factory.parse(doc); > XmlCursor cursor = xml.newCursor(); > cursor.push(); cursor.selectPath(query); > > it gives me the correct result (<c/>). > > But if if the document comes with a namespace, for instance: > > > <a xmlns="mynamespace"> > <b/> > </a> > > > the same code does not give me any result. > > After investigating I found that a working code could be: > > > String doc = "<a xmlns="mynamespace"><b/></a>"; > String query = "declare namespace xs='mynamespace';/xs:a/xs:b"; > XmlObject xml = XmlObject.Factory.parse(doc); > XmlCursor cursor = xml.newCursor(); > cursor.push(); cursor.selectPath(query); > > Is there a better way to do this without having to set the prefix "xs:" > in the Xpath query for each level ? I would like to find a generic way to > handle XML documents with or without namespace. > > Regards, > Pascal > > > Notice: This email message, together with any attachments, may contain > information of BEA Systems, Inc., its subsidiaries and affiliated entities, > that may be confidential, proprietary, copyrighted and/or legally > privileged, and is intended solely for the use of the individual or entity > named in this message. If you are not the intended recipient, and have > received this message in error, please immediately return this by email > and then delete it. > > Notice: This email message, together with any attachments, may contain > information of BEA Systems, Inc., its subsidiaries and affiliated > entities, that may be confidential, proprietary, copyrighted and/or > legally privileged, and is intended solely for the use of the individual > or entity named in this message. If you are not the intended recipient, > and have received this message in error, please immediately return this > by email and then delete it. --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
