I'd have to see the Schema to be able to figure out the name of elements
and types and what the exact code should look like. I think that your
problem might be that <element> is not a global Schema type and so
auto-typing doesn't work if at the root level (in other words, Schema
doesn't allow <element> to be a top-level element).
But even then, you should not have to parse and save to String only to
parse again.
Radu
On Tue, 2008-04-08 at 06:49 -0700, Pascal Maugeri wrote:
> Hi
>
> I would like to have a clarification about the parsing of a XML
> fragment.
>
> For instance, having the following XML document, I want to obtain the
> "uri" attribute value:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <doc>
> <element uri="www.apache.org"/>
> </doc>
>
> with
> Doc.Factory.parse(xml).getDoc().getElement().getUri()
> it returns the attribute value.
>
> but with
> Element.Factory.parse("<element uri=\"www.apache.org\"/>").getUri()
> it returns null, also a call to Element.Factory.parse("<element uri=
> \"www.apache.org\"/>").toString() returns the XML content.
>
> As I do need to parse XML fragment such as this "element", I have
> found the following workaround:
> a) I get the String representation of the Element (eg.
> Element.Factory.parse(...).toString() ),
> b) I insert the result of (a) into a container <doc>...</doc>
> c) then I parse the result of (b) with the
> Doc.Factory.parse( (b) ).getDoc().getElement().getUri() and it does
> work.
> ... also I'm not very proud of myself :-)
>
> Could you explain why I can't access the attributes of a XML fragment
> I parsed ?
>
> I there a better/cleaner workaround than the one above ?
>
> Thanks in advance for your help
> Pascal
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