Thanks to both for your answers and suggestions. It's getting clearer to
me...
Radu, what is the content of this file test.xml in your test ? I guess only
<element/> ?
Remember, I have only the schema (and the corresponding beans) then I
receive this fragment <element/> that I want to parse.
Regards,
Pascal
On Tue, Apr 29, 2008 at 2:27 AM, Radu Preotiuc-Pietro <[EMAIL PROTECTED]> wrote:
> Actually, I have made some experiments myself and you may have success
> with something like:
>
> DocDocument.Doc doc = (DocDocument.Doc) XmlObject.Factory.parse(new
> File("test.xml"), new
> XmlOptions().setDocumentType(DocDocument.Doc.type));
>
> to parse from the <element> level.
>
> Let me know if this works for you,
> Radu
>
> > -----Original Message-----
> > From: Jim the Standing Bear [mailto:[EMAIL PROTECTED]
> > Sent: Monday, April 28, 2008 8:38 AM
> > To: [email protected]
> > Subject: Re: Parsing an XML fragment
> >
> > I ran into the same problem and toyed around it over the weekend.
> > what I found out was that it helps if you parse it from "a level up".
> >
> > So in your case, you would have to parse it from the Document
> > level, since that is the only thing above "Element" nodes.
> >
> > In other words, doing
> > Doc.Factory.parse(xml).getDoc().getElement().getUri() is the
> > way to go. However, you said you needed to parse from
> > Element level - is there any constraints that force you to
> > parse from Element level?
> >
> > HTH
> >
> > Jim
> >
> >
> >
> > On Mon, Apr 28, 2008 at 6:17 AM, Pascal Maugeri
> > <[EMAIL PROTECTED]> wrote:
> > > Radu
> > >
> > > You're right in the example below the <element> is not a
> > global schema type.
> > >
> > > So what should I do if a server (XCAP server) sends me this
> > XML fragment:
> > >
> > >
> > > <element uri="www.apache.org"/>
> > >
> > > and I want to parse it having the xml beans set from the
> > corresponding
> > > schema ?
> > >
> > > Is there a way to do that ?
> > >
> > > Regards,
> > > Pascal
> > >
> > >
> > >
> > >
> > > On Sat, Apr 19, 2008 at 3:35 AM, Radu Preotiuc-Pietro
> > <[EMAIL PROTECTED]> wrote:
> > >
> > > > I'd have to see the Schema to be able to figure out the name of
> > > > elements and types and what the exact code should look
> > like. I think
> > > > that your problem might be that <element> is not a global Schema
> > > > type and so auto-typing doesn't work if at the root level
> > (in other
> > > > words, Schema doesn't allow <element> to be a top-level element).
> > > >
> > > > But even then, you should not have to parse and save to
> > String only
> > > > to parse again.
> > > >
> > > > Radu
> > > >
> > > >
> > > >
> > > >
> > > > On Tue, 2008-04-08 at 06:49 -0700, Pascal Maugeri wrote:
> > > > > Hi
> > > > >
> > > > > I would like to have a clarification about the parsing of a XML
> > > > > fragment.
> > > > >
> > > > > For instance, having the following XML document, I want
> > to obtain
> > > > > the "uri" attribute value:
> > > > >
> > > > > <?xml version="1.0" encoding="UTF-8"?>
> > > > > <doc>
> > > > > <element uri="www.apache.org"/>
> > > > > </doc>
> > > > >
> > > > > with
> > > > > Doc.Factory.parse(xml).getDoc().getElement().getUri()
> > > > > it returns the attribute value.
> > > > >
> > > > > but with
> > > > > Element.Factory.parse("<element
> > > > > uri=\"www.apache.org\"/>").getUri()
> > > > > it returns null, also a call to Element.Factory.parse("<element
> > > > > uri=
> > > > > \"www.apache.org\"/>").toString() returns the XML content.
> > > > >
> > > > > As I do need to parse XML fragment such as this
> > "element", I have
> > > > > found the following workaround:
> > > > > a) I get the String representation of the Element (eg.
> > > > > Element.Factory.parse(...).toString() ),
> > > > > b) I insert the result of (a) into a container <doc>...</doc>
> > > > > c) then I parse the result of (b) with the
> > Doc.Factory.parse( (b)
> > > > > ).getDoc().getElement().getUri() and it does work.
> > > > > ... also I'm not very proud of myself :-)
> > > > >
> > > > > Could you explain why I can't access the attributes of a XML
> > > > > fragment I parsed ?
> > > > >
> > > > > I there a better/cleaner workaround than the one above ?
> > > > >
> > > > > Thanks in advance for your help
> > > > > Pascal
> > > >
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> >
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