Hi Camel-Users
I have a workflow where files are moved from an input-directory to a
processing-directory and later to an error- or target-directory. Out of the
file content messages are generated (Claim Check Pattern) and if an error
occurs during processing of the message, it is sent to an error-queue. The
file stays in the processing directory.
I am consuming the messages from the error queue with another Camel route
(this is done by an own component). This route currently dumps the
exception content from the message header to a file:
from(errorQueue)
.routeId(ROUTE_ID_ERROR) .unmarshal(jaxb)
// dump exception to a file .setHeader(Exchange.FILE_NAME, new
CreateErrorFilename()) .setBody(header(EXCEPTION_STACKTRACE)) .to("file:" +
errorFileDirectory + "?fileExist=Fail"); // how to move associated file
from processing to error-directory? ;
But as another step I need to move the associated file (filename is in
message header) from the processing-directory to the error-directory. How
can I do this?
The Camel file component is a consumer. I would need something like a
processor. Is this file move possible inside the Camel route or do I have
to implement it with plain Java and call it as a bean?
Thanks
Stephan
