Hi Yeah just write a java bean to move/rename the file.
On Thu, May 16, 2013 at 12:40 PM, Stefan Burkard <sburk...@gmail.com> wrote: > Hi Camel-Users > > I have a workflow where files are moved from an input-directory to a > processing-directory and later to an error- or target-directory. Out of the > file content messages are generated (Claim Check Pattern) and if an error > occurs during processing of the message, it is sent to an error-queue. The > file stays in the processing directory. > > I am consuming the messages from the error queue with another Camel route > (this is done by an own component). This route currently dumps the > exception content from the message header to a file: > > from(errorQueue) > .routeId(ROUTE_ID_ERROR) .unmarshal(jaxb) > // dump exception to a file .setHeader(Exchange.FILE_NAME, new > CreateErrorFilename()) .setBody(header(EXCEPTION_STACKTRACE)) .to("file:" + > errorFileDirectory + "?fileExist=Fail"); // how to move associated file > from processing to error-directory? ; > But as another step I need to move the associated file (filename is in > message header) from the processing-directory to the error-directory. How > can I do this? > > The Camel file component is a consumer. I would need something like a > processor. Is this file move possible inside the Camel route or do I have > to implement it with plain Java and call it as a bean? > > Thanks > Stephan -- Claus Ibsen ----------------- www.camelone.org: The open source integration conference. Red Hat, Inc. FuseSource is now part of Red Hat Email: cib...@redhat.com Web: http://fusesource.com Twitter: davsclaus Blog: http://davsclaus.com Author of Camel in Action: http://www.manning.com/ibsen