Here is how I would do it. I provide both a “short” solution and a “long” one.
I would use the “short” solution if I was making for example a developer only
tool and I knew I was only hashing small things for example a configuration
file in a build script and want a one-liner. Otherwise I’d use the “long”
version.
//If the content is guaranteed to be short:
def content = new ByteArrayInputStream("Here be dragons".bytes)
println MessageDigest.getInstance("SHA1").digest(content.bytes).encodeHex()
//If the content might be arbitrarily long:
content = new ByteArrayInputStream("Here be dragons".bytes)
def digest = MessageDigest.getInstance("SHA1")
content.eachByte(4096) { bytes, len ->
digest.update(bytes, 0, len)
}
println digest.digest().encodeHex()
Jason
From: Gerald Wiltse [mailto:[email protected]]
Sent: Friday, March 04, 2016 9:18 AM
To: [email protected]
Subject: Groovy Hash Calculations
Hello All,
I have this block, it's pretty compressed, just wondering if there is a more
groovy way to handle reading the buffer and computing the hash.
def messageDigest = MessageDigest.getInstance("SHA1")
def dis = new DigestInputStream(content, messageDigest)
byte[] buffer = new byte[1024];
while (dis.read(buffer) != -1) {}
def sha1Hex = new BigInteger(1,
messageDigest.digest()).toString(16).padLeft(40, '0')
Gerald R. Wiltse
[email protected]<mailto:[email protected]>
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