Yeah, I misspoke when I said LuaHookInsertFilter; that isn’t actually implemented yet at least on 2.4. Actually have been trying the quick handler and hookfixups.
What hook should I be using? What value do I return from my handler so that Apache will still send the request onto the reverse proxy? I feel like this (http://www.modlua.org/recipes/loadbalancing) may be what I want, but I don’t know how to hook that into my httpd.conf file. Does this tie into mod_proxy at all, or is this instead of? In that example, what is the magic string “proxy-server”?: function proxy_handler(r) r.handler = "proxy-server" r.proxyreq = apache2.PROXYREQ_REVERSE r.filename = "proxy:" .. backends[math.random(1,#backends)] .. r.uri return apache2.DECLINED -- let the proxy handler do this instead end On April 15, 2016 at 9:47:01 PM, Eric Covener (cove...@gmail.com) wrote: On Fri, Apr 15, 2016 at 9:10 PM, Matt Hughes <hughes.m...@gmail.com> wrote: > I currently have Apache setup as a reverse proxy to another server. > > I was hoping to use mod_lua to slightly tweak the request body of incoming > requests before sending them off to the other server. I have mod_lua setup > enough so that I have a LuaHookInsertFilter that is pointing to my > LuaInputFilter. But the question is, what does the function in the > LuaHookInsertFilter have to return so that the modified request continues on > to the proxy? > > Right now I have something like: > > function handle(r) > r.info(r, "example handler called") -- debug print > r:add_input_filter("myInputFilter") > return apache2.PROXYREQ_REVERSE > end > > Am I using the right LuaHook? Any examples would be greatly appreciated. Looks right to me. The underlying hook for "insert_filter" expects a void return. This means everyone who is registered gets called every time. --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@httpd.apache.org For additional commands, e-mail: users-h...@httpd.apache.org
