What it's the equation you need to compute ?Perhaps I can help.
I think it's possible to compute with something in this way:
map = find (P(:,2) > 100 );
if batt > 800 then
batt = batt - P(map,2) * (P(map+1,1) - P(map,1));
end
On Wed, 2017-05-10 at 17:23 +0200, Frieder Nikolaisen wrote:
> Hello,
>
> I did write an example code, but I do not like the time consuming way
> I solved the problem. With 50 000 lines in the matrix, it wouldn't be
> fun.
>
> How can I avoid using the for-loop?
>
> 10, 80;
> 11, 200
> 15, 0];
>
> batt = 1000;
> gen = 0;
>
> n = 1
> for n=1:5
>
> if P(n,2) > 100 then
> if batt > 800 then batt = batt - P(n,2) * (P(n+1,1) - P(n,1))
> else
> gen = gen + P(n,2) * (P(n+1,1) - P(n,1))
> end
>
> else
> batt = batt - P(n,2) * (P(n+1,1) - P(n,1))
> end
> disp('n ' + string(n))
> disp('batt ' + string(batt))
> disp('gen ' + string(gen))
> end
>
>
> Thanks alot!
>
>
>
> Best regards
> Frieder
>
>
>
>
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