Le 05/12/2019 à 14:25, Federico Miyara a écrit :
Dear all,
When using makecell such as in
--> u = makecell([2 2], cos, 'hello', 1+%s^2, [1 2; 3 4])
u =
[ 1 fptr ] [1x1 string ]
[1x1 polynomial] [2x2 constant]
we get a cell array where the unidimensional ordering of the cells
goes first along columns and then ows. However, when extracting
components unidimensionally, it behaves the other way around:
--> u(1:4)
ans =
[ 1 fptr ]
[1x1 polynomial]
[1x1 string ]
[2x2 constant ]
The same happens wen applying matrix:
--> matrix(u,4,1)
ans =
[ 1 fptr ]
[1x1 polynomial]
[1x1 string ]
[2x2 constant ]
--> matrix(u,1,4)
ans =
[1 fptr] [1x1 polynomial] [1x1 string] [2x2 constant]
Isn't this inconsistent?
Shouldn't makecell create the cell array going along rows and then
columns?
No, the doc says:
s= makecell(dims,a1,a2,...an) creates a cell array of dimensions given
by dims with the given input arguments. The ai are stored along the last
dimension first.
Regards,
Federico Miyara
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Stéphane Mottelet
Ingénieur de recherche
EA 4297 Transformations Intégrées de la Matière Renouvelable
Département Génie des Procédés Industriels
Sorbonne Universités - Université de Technologie de Compiègne
CS 60319, 60203 Compiègne cedex
Tel : +33(0)344234688
http://www.utc.fr/~mottelet
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