Hi Anonimus,
What exception do you get when you don't specify CascadeType.PERSIST?
I'm assuming you're doing something like this :
Employee e = new Employe();
e.setName("John Doe");
Department d = em.find(Department.class, idDept); // this is what I think
you mean by loading all the references.
e.setIdDepartment(d);
Rank r = em.find(Rank.class, idRank);
e.setIdRank(r);
// and so on
em.persist(e);
If that's the case then you shouldn't get any exceptions.
Thanks,
-Mike
On Wed, Jun 11, 2008 at 8:52 AM, Anonimus <[EMAIL PROTECTED]> wrote:
>
>
> Ognjen Blagojevic wrote:
> >
> > It must be a way to INSERT objects in the database without looking up
> > for all the references, but I am not able to find it.
> >
>
> My problem is similar as yours, with a single difference.
> I don't mind loading all the references because I need them in the program.
> But I don't know how to insert object and disable an attempt of inserting
> in
> related tables. If I put cascade = cascadeType.PERSIST, I get an exception
> (as you do). If I don't put cascade = cascadeType.PERSIST (which is
> logical), I get an exception. Since I'm new in JPA, I'm quite lost now.
>
> --
> View this message in context:
> http://www.nabble.com/How-to-PERSIST-object-without-loading-references--tp16472647p17778155.html
> Sent from the OpenJPA Users mailing list archive at Nabble.com.
>
>
