Create a method in the class of the page or component from where you're
making the call like this:
public String getMyEventUrl(){
return componentResources.createEventLink("myEvent").toURI();
}
Then on the template your javascript can be something like:
Ajax.Request('${myEventUrl}')
On Fri, Apr 17, 2009 at 10:15 PM, roubaozi <[email protected]> wrote:
>
> Hi,
>
> I am trying to use Tapestry 5.0.18 to finish a small project I am working
> on, and I am stuck.
>
> I am trying to accomplish an ajax call from the client side using prototype
> Ajax.Request(), and on the server side I am trying to update a
> persist(session) property in the page class when the ajax request gets to
> the server side. I know all Tapestry ajax approaches are like a mixin or
> event binded to a component, and use an event handler method on the server
> side to process the request. But my situation is, there is no component I
> can bind to, I am triggering the ajax request with some events like
> window.onload() or ontimeout() which don't have a Tapestry component I can
> bind to.
>
> So how do I send an ajax request from client to a method on the server
> side?
> how do I create the url which the ajax.request is sending to?
>
> Thanks in advance.
> --
> View this message in context:
> http://www.nabble.com/An-ajax-question-%28sending-ajax-request-without-binded-to-a-component%29-tp23105754p23105754.html
> Sent from the Tapestry - User mailing list archive at Nabble.com.
>
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