Thanks for the reply, I should have thought about that.

HugoPalma wrote:
> 
> Create a method in the class of the page or component from where you're
> making the call like this:
> 
> public String getMyEventUrl(){
>   return componentResources.createEventLink("myEvent").toURI();
> }
> 
> Then on the template your javascript can be something like:
> 
> Ajax.Request('${myEventUrl}')
> 
> On Fri, Apr 17, 2009 at 10:15 PM, roubaozi <lagjazz.j...@gmail.com> wrote:
> 
>>
>> Hi,
>>
>> I am trying to use Tapestry 5.0.18 to finish a small project I am working
>> on, and I am stuck.
>>
>> I am trying to accomplish an ajax call from the client side using
>> prototype
>> Ajax.Request(), and on the server side I am trying to update a
>> persist(session) property in the page class when the ajax request gets to
>> the server side. I know all Tapestry ajax approaches are like a mixin or
>> event binded to a component, and use an event handler method on the
>> server
>> side to process the request. But my situation is, there is no component I
>> can bind to, I am triggering the ajax request with some events like
>> window.onload() or ontimeout() which don't have a Tapestry component I
>> can
>> bind to.
>>
>> So how do I send an ajax request from client to a method on the server
>> side?
>> how do I create the url which the ajax.request is sending to?
>>
>> Thanks in advance.
>> --
>> View this message in context:
>> http://www.nabble.com/An-ajax-question-%28sending-ajax-request-without-binded-to-a-component%29-tp23105754p23105754.html
>> Sent from the Tapestry - User mailing list archive at Nabble.com.
>>
>>
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>>
> 
> 

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