Thanks guys!
Ole
On 09/03/2011 10:51 AM, Konstantin Preißer wrote:
Hi,
-----Original Message-----
From: Jonathan Soons [mailto:jso...@juilliard.edu]
Sent: Saturday, September 03, 2011 2:24 PM
To: Ole Ersoy; Tomcat Users List
Subject: RE: Servlet 3.0 File Upload
You need to add a line in in your form:
<input type="text" name="filename" />
Then in your servlet GetPost() method you put this filename in a
variable:
String filename;
filename = req.getParameter("filename");
Then instead of part.write("samplefile");
do:
part.write(filename);
Doesn't that mean that the user has to enter the filename by himself?
What I usually do to get the filename is:
Part uploadPart = request.getPart("uploadfield"); // get the Part
String contDispoHeader = uploadPart.getHeader("Content-Disposition"); // get
Content-Disposition header
String uploadFilename = null;
if (contDispoHeader != null) {
try {
uploadFilename = new
ContentDisposition(contDispoHeader).getParameter("filename");
} catch (ParseException e) { }
}
Note that "ContentDisposition" class is from JavaMail package
(javax.mail.internet.ContentDisposition). Browser usually send filenames in the
"filename" parameter of a Content-Disposition header.
Regards,
Konstantin Preißer
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