you need to be able to know not just the label but the full path. then use your TreeModel impl to locate the node...
-igor On Fri, Mar 21, 2008 at 1:24 AM, bhitai <[EMAIL PROTECTED]> wrote: > > Hi > I'm kinda new to Apache wicket. I have a LinkTree on a page on which I also > have other Ajax enabled components (basically 5,6 links on the page). When > my other component is clicked, I want to locate the node in the tree and > expand it, to show the user's selection. I know tree.getTreeState() will > allow me to expand a particular tree node, but I can't seem to find a way to > locate the treeNode inside the tree in the first place. I have the label of > the node coming back in the Ajax model, and I'm wondering if I can navigate > to that particular node (all names are unique in this scenario) using the > label string to search in the tree. > > thanks in advance, > jaffry > > -- > View this message in context: > http://www.nabble.com/AjaxTree-%3A-how-to-locate-a-node-based-on-its-label-tp16194936p16194936.html > Sent from the Wicket - User mailing list archive at Nabble.com. > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
