All looks good to me, my guess is that you aren't entering in a name,
and so you're failing validation, but you haven't implemented onError
to add the feedback panel to the target in that case. Also, your
feedback panel probably needs setOutputMarkupId(true) to be of any
use, given that you're submitting with ajax.
-Clint
On Sun, Apr 19, 2009 at 9:11 AM, HHB <hubaghd...@yahoo.ca> wrote:
> Hey,
> I have a form and I want to submit it via Ajax:
>
> <wicket:panel>
> <form wicket:id="form">
> <div wicket:id="feedback"></div>
> <table width="100%" cellpadding="2" cellspacing="2">
> <tr>
> <td><label><wicket:message key="name"/>
> </label></td>
> <td><span wicket:id="nameBorder">
> <input type="text" wicket:id="name"/></span></td>
> </tr>
> <tr>
> <td><wicket:message key="note"/></td>
> <td><textarea cols="20" rows="10"
> wicket:id="note"></textarea></td>
> </tr>
> <tr>
> <td colspan="2">
> <input wicket:id="create" type="button" value="Create Group"/></td>
> </tr>
> </table>
> </form>
> </wicket:panel>
>
> public CreateGroupPanel(String id) {
> super(id);
> setOutputMarkupId(true);
> final Form form = new Form("form",
> new CompoundPropertyModel(new Group()));
> add(form);
> form.add(new FeedbackPanel("feedback"));
> form.add(new
> FormComponentFeedbackBorder("nameBorder").add(new
> TextField("name").setRequired(true)));
> form.add(new TextArea("note"));
> form.add(new AjaxSubmitLink("create") {
> �...@override
> protected void onSubmit(AjaxRequestTarget target,
> Form form) {
> Group group = (Group) form.getModelObject();
> System.out.println("Logging: " + group);
> }
> });
> }
>
> But nothing is got print on the console.
> Any ideas what is going wrong?
> FireFox 3.0.7
> Ubuntu 8.10
> Wicket 1.3.5
> Thanks.
>
>
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