Yes, you are right.
My isssue is solved now, thanks.
cpopetz wrote:
>
> All looks good to me, my guess is that you aren't entering in a name,
> and so you're failing validation, but you haven't implemented onError
> to add the feedback panel to the target in that case. Also, your
> feedback panel probably needs setOutputMarkupId(true) to be of any
> use, given that you're submitting with ajax.
>
> -Clint
>
> On Sun, Apr 19, 2009 at 9:11 AM, HHB <hubaghd...@yahoo.ca> wrote:
>> Hey,
>> I have a form and I want to submit it via Ajax:
>>
>> <wicket:panel>
>> <form wicket:id="form">
>> <div wicket:id="feedback"></div>
>> <table width="100%" cellpadding="2" cellspacing="2">
>> <tr>
>> <td><label><wicket:message key="name"/>
>> </label></td>
>> <td>
>> <input type="text" wicket:id="name"/></td>
>> </tr>
>> <tr>
>> <td><wicket:message key="note"/></td>
>> <td><textarea cols="20" rows="10"
>> wicket:id="note"></textarea></td>
>> </tr>
>> <tr>
>> <td colspan="2">
>> <input wicket:id="create" type="button" value="Create Group"/></td>
>> </tr>
>> </table>
>> </form>
>> </wicket:panel>
>>
>> public CreateGroupPanel(String id) {
>> super(id);
>> setOutputMarkupId(true);
>> final Form form = new Form("form",
>> new CompoundPropertyModel(new Group()));
>> add(form);
>> form.add(new FeedbackPanel("feedback"));
>> form.add(new
>> FormComponentFeedbackBorder("nameBorder").add(new
>> TextField("name").setRequired(true)));
>> form.add(new TextArea("note"));
>> form.add(new AjaxSubmitLink("create") {
>> �...@override
>> protected void onSubmit(AjaxRequestTarget target,
>> Form form) {
>> Group group = (Group) form.getModelObject();
>> System.out.println("Logging: " + group);
>> }
>> });
>> }
>>
>> But nothing is got print on the console.
>> Any ideas what is going wrong?
>> FireFox 3.0.7
>> Ubuntu 8.10
>> Wicket 1.3.5
>> Thanks.
>>
>>
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>>
>
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