Hi,
I'd recommend you to use plain JS to make the Label visible.
AjaxButton yourAjaxButtonWithResource = new AjaxButton("button) {
@Override protected void updateAjaxAttributes(AjaxRequestAttributes
attributes) {
attributes.getAjaxCallListeners().add(new
AjaxCallListener().onBeforeSend("$('#labelId').show()"));
}
...
}
Martin Grigorov
Wicket Training and Consulting
https://twitter.com/mtgrigorov
On Thu, Mar 2, 2017 at 7:29 PM, SeldonCrisis <[email protected]> wrote:
> OK, thanks Ernesto and everyone else.
>
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