Would someone please explain the usage of @=. I am getting confuse from the help file.
[EMAIL PROTECTED] Matches the preceding atom with zero width. {not in Vi} Like "(?=pattern)" in Perl. Example matches ~ foo\(bar\)[EMAIL PROTECTED] "foo" in "foobar" foo\(bar\)[EMAIL PROTECTED] nothing To me, the second example matches nothing because there is no foo in between the \( and \) The first example, I am all confused. If someone can enlighten me, I would be greatful. Michael D. Phillips - A computer science enthusiast I do not hate Windows, I just like the alternatives better. Linux is my primary choice. ____________________________________________________________________________________ Don't get soaked. Take a quick peek at the forecast with the Yahoo! Search weather shortcut. http://tools.search.yahoo.com/shortcuts/#loc_weather