Axil, much better said than my relativistic warp via confinement but we are on 
the same page. IMHO even catalytic action is a weak form of this mechanism. I 
think catalysis is just the rate of change in low level dilation due to the 
tapestry of geometry in active regions. I think LENR is bootstrapped from an 
intense form of catalysis where the dilation factors reach relativistic levels 
and because they are based on an inverse square cube [Casimir or other London 
form] they trump the gravitational square law causing breaches in the isotropy 
that LENR exploits.
Regards
Fran

From: Axil Axil [mailto:janap...@gmail.com]
Sent: Thursday, August 13, 2015 10:05 PM
To: vortex-l
Subject: EXTERNAL: Re: [Vo]:Re: Muons, SPP, DDL & RPF

The muon decays when a W- appears from the vacuum. This appearance is timed by 
the probability of the decay of the muon. But if the vacuum is energized so 
that it has an excess of positive vacuum energy. then the W- will not appear on 
time, it will be delayed.Excess vacuum energy slows down time.  A excess of 
positive vacuum energy appears if a corresponding zone of negative vacuum 
energy is present.

That zone of negative vacuum energy exists inside the SPP.  Negative vacuum 
energy speeds up time a lot. This acceleration of time is why radioactive 
isotopes produced by fusion in LENR decay almost instantaneously. That is 
because the ash from a fusion event is entangled with the inside of the SPP in 
which all the energy of the fusion event is delivered.

On Thu, Aug 13, 2015 at 8:31 PM, Bob Cook 
<frobertc...@hotmail.com<mailto:frobertc...@hotmail.com>> wrote:
Jones, Eric and Axil--

I have been trying to understand the mechanism of muon decay, but am still in 
the dark.

The muon is said to be a lepton—a primary particle not made of any 
constitutents—yet it frequently decays into three particles, including 
neutrinos that are normally not observed but inferred.
The standard words  explain that muon decays by a weak force interaction, 
however an interaction with what?—it’s not said.   And what happens to a muon, 
if it is in empty space with nothing with which to interact?

It seems W+, W- and Z^0 (0 charge)  bosons, the carriers of the weak force, are 
involved, but do they appear  at random from the vacuum to disrupt a free muon, 
causing it to decay?  And why is the half life of a free muon so short?  If a 
massive boson mediates the decay, what happens to the boson?  Does it disappear 
back to the vacuum?  The bosons are said to be very short lived--10^-18 sec.

Bob Cook






.





From: Axil Axil<mailto:janap...@gmail.com>
Sent: Thursday, August 13, 2015 11:09 AM
To: vortex-l<mailto:vortex-l@eskimo.com>
Subject: Re: [Vo]:Re: Muons, SPP, DDL & RPF

There are indications that Muons are extended in there lifetimes by Rysberg 
matter. The muons are produced for hours and days after the Rydberg matter is 
exposed to light.

As referenced from the HolMlid paper as follows:

" The sources give a slowly decaying muon signal for several hours and days 
after being used for producing H(0). They can be triggered to increase the muon 
production by laser irradiation inside the chambers or sometimes even by 
turning on the fluorescent lamps in the laboratory for a short time."

But in the experiment, the ability to extend the lifetime of muons is not open 
ended in time. There is a reduction of muon detection over time. If the ability 
for Rydberg matter to extend the lifetime of muons was open ended, the count of 
detected muons would reach a stable condition since cosmic muons arrive at a 
relitivly constant rate. .

I believe that this ability to extend Muon lifetimes is rooted in the coherent 
superconductive nature of Rydberg matter.

Furthermore, the mean energy of cosmic muons reaching sea level is about 4 GeV. 
Muons, This energy level is higher than the levels seen by Holmlid in his 
experiment. This implies that the muions seen in the experiment were produced 
locally by Rydberg matter.

On Thu, Aug 13, 2015 at 10:38 AM, Jones Beene 
<jone...@pacbell.net<mailto:jone...@pacbell.net>> wrote:

To paraphrase what Bob has said and cited, there is little possibility of a 
spin problem, when it is proposed that the SPP can extend the lifetime of muons 
(as opposed to creating them from nothing).

I think that we all agree that “extending the lifetime” of a catalytic particle 
like the muon, where there is already a flux coming from the natural source – 
is functionally identical to “making” them anew. In either case, a higher 
population accumulates. Since any interaction with protons would happen within 
the geometry of the strong force, it is subject to QCD, and consequently 
giga-eV are in play, so the source of energy is no mystery. Proton mass is not 
quantized.

In the end, until Holmlid’s experiment is better explained as something other 
than detection of muons in a situation where SPP are acting on dense hydrogen, 
he should be given benefit of the doubt. No?

This would mean that a valid, if not intuitive, explanation for the thermal 
anomaly in the glow-type reactor (incandescent reactor) involves muons 
interacting catalytically with protons, where the muons appear to be either 
created from the reaction, or else do not decay as normal, following the 
reaction. This scenario will include a thermal anomaly which does not involved 
gamma radiation.

This M.O. leaves open three possibilities for explaining the thermal anomaly – 
one which is covered by Storms. He suggests that protons fuse to deuterium, 
despite the spin problem, and lack of evidence in the ash. Another possibility 
is that SPP formation is inherently energetic – but this is unlikely since SPP 
are seen in optoelectronics with no energy gain. My suggestion is simpler and 
based on the solar model. It suggests that the catalyzed fusion reaction 
happens but is instantly reversible, due to Pauli exclusion. Excess energy 
derives from conversion of a portion of proton mass to energy via QCD during 
the brief time when the diproton exists as a helium-2 nucleus, before reverting 
to two protons and a renewed muon.

Until there is evidence of deuterium in the ash we have an ongoing debate in 
which the physical evidence favors one argument over the other.

From: Bob Cook

Eric--



Note my comment to Jones before I read your questions.



Bob



From: Eric Walker<mailto:eric.wal...@gmail.com>



Jones Beene  wrote:

    D+D + muon → helium-4 + muon (instead of gamma)

… where the fist muon can be a cosmic muon which can catalyze a reaction and 
then be rejuvenated, renewed or replaced by the same fusion reaction that it 
catalyzes.

The muon is a “heavy electron” with a short life, but now we can surmise that 
it can have its lifetime greatly extended as part of the catalysis. The 
probability for this to occur is larger than zero, but how large? … “Maybe it’s 
pretty high” says Byrnes. Can it explain the lack of gamma, as well? Probably. 
But now, as we are learning – this rebirth effect will be more robust with SPP 
and fractional hydrogen.

A muon could possibly carry away as kinetic energy the energy that would 
otherwise go to a gamma.  But if we're talking about a single muon, how do you 
propose that the spin of the missing photon is conserved?



Eric




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