Robin and Eric--
You are correct based on data associated with two particle (nuclei and
neutron) absorption reactions. I agree that there will be prompt gammas
associated with most if not all neutron absorption reactions, since there is
no coupling to transfer energy from the new isotope to an assemblage of
other particles--a coherent system.
However, it may be that a coherent system of Ni may absorb a neutron and
distribute the excess energy to many particles, including electrons, of
system. This has been my assumption for some time that the energy
coupling in the LENR reactions is via spin energy sharing within the
coherent system. The no-gamma experience has never made sense with the
transmutations and other ash seen in LENR. I would assume you would
consider that the transmutations did not occur without gammas.
We differ in that I believe they have occurred without gammas. It's too
easy to measure gammas for so many experimenters to have missed them.
Bob Cook
-----Original Message-----
From: Bob Cook
Sent: Thursday, October 15, 2015 10:23 PM
To: [email protected]
Subject: [Vo]:Re: Swedish scientists claim LENR explanation break-through
In reply to Mixent:
I disagree with your comment that every reaction is going to produce an
energetic gamma immediately. Most of the Ni isotopes that absorb a neutron
are stable or decay by a beta ray. I noted the radioactive Ni isotopes that
have a gamma in their decay mode.
Li-7 goes to Li-8 and hence to Be-8 without any gamma. It ends up expelling
a beta and two alphas I believe. O-16 with a neutron goes to stable O-17
and it goes to O-18 which is also stable.
Bob Cook
-----Original Message-----
From: [email protected]
Sent: Thursday, October 15, 2015 9:36 PM
To: [email protected]
Subject: Re: [Vo]:Re: Swedish scientists claim LENR explanation
break-through
In reply to Bob Cook's message of Thu, 15 Oct 2015 21:26:22 -0700:
Hi,
[snip]
It doesn't matter which element/isotope absorbs the neutron, or which
isotope it
creates. Every reaction is going to produce an energetic gamma immediately.
ALL
the excess energy from this process is going to be in the form of gammas,
and
most of them are going to escape the device, accomplishing two things:-
1) There will be very little left to provide heating to continue the
process.
2) The researchers will soon die of a severe radiation overdose.
RE: [Vo]:Swedish scientists claim LENR explanation break-throughJones--
It was my conclusion reading the paper that the energy required to free a
neutron from Li-7 produced a thermal neutron which could be readily
absorbed by Ni-58. Note the paper does not address the use of other
isotopes of Ni. Natural Ni would pose a radioactive hazard if it is
sufficiently exposed to thermal neutrons. An assessment of the thermal
neutron flux in a Ni nano particle, based on the estimated production of
spalled neutrons would be a desirable side calculation.
The paper makes note of the control of neutrons embodied within the Ni in
order to prevent outside activation—see the 3rd paragraph on page 4.
There are a number of isotopes that can capture a neutron and still remain
stable.
From: Jones Beene
Sent: Thursday, October 15, 2015 12:48 PM
To: [email protected]
Subject: RE: [Vo]:Swedish scientists claim LENR explanation break-through
From: MarkI-ZeroPoint
Ø
Ø I posted a ref from physorg ... It involves a new observation about
resonance which might tie in with the Swede’s paper...
Mark, No problem with the resonance. It’s the neutrons that are the
problem.
What the Swedes should know, but apparently do not fully appreciate, is
that neutrons simply cannot be involved as a modality in LENR, since there
is no induced radioactivity. It is as simple as that. In fact, their theory
is almost an embarrassment.
Neutrons are insidious and difficult to contain. Even at the lowest energy
(ultra-cold), neutrons will eventually activate almost everything they come
in contact with. The good news would be – this activation should serve as
instant proof of LENR when it happens, but the bad news is that it never
happens.
Most of the mass of the Hot Cat is the element aluminum – in the form of
alumina ceramic. Neutron activation of aluminum occurs by numerous neutron
capture reactions and the cross-section is substantial for thermal neutrons
(few barns) and gets higher with colder neutrons. Such reactions as 27Al +
n = 28Al, 27Al(n,a) 24Na, 27Al(n,2n)26Al and 27Al(n,p)27Mg show up at once.
Even if by some miracle, only one neutron out of a million diffuses to the
tube wall - these insidious little bastards would activate the alumina into
a radioactive health hazard within minutes of excess heat showing up. The
excited states following activation will undergo beta decay over protracted
time periods and emit gammas as the nuclei de-excite to their respective
ground states. Radioactivity would continue for months.
Since this does not happen, we can be almost certain that neutrons are not
involved in the Hot Cat operation.
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/project.html
