Bob
Why does the electron charge to mass ratio come out in support of it having 511 keV of energy if it really has much more? That seems contradictory. The way I understand it, all of the energy has a mass equivalent. Dave -----Original Message----- From: Bob Higgins <rj.bob.higg...@gmail.com> To: vortex-l <vortex-l@eskimo.com> Sent: Sun, Oct 25, 2015 3:05 pm Subject: Re: [Vo]:slide deck for ultradense hydrogen / Leif Holmlid That is the energy given off to send the normal space positronium atom into a DDL-like minimum energy orbit. When the electron-positron orbiting pair becomes in the DDL orbit (orbital radius about the diameter of a proton), it becomes undetectable and it is part of the negative energy sea. It is still polarizable and it is the displacement of the epo sea that provides electromagnetic "displacement". According to Hotson, the epo (in the DDL orbit) has no inertial mass - for explanation of the origin of mass you will have to read Hotson's papers. The epo sea IS the inertial mass-less ether. Note that the 511keV is NOT the total energy of the electron. When the spin energy of the electron is included, the total energy is over 16MeV. The 1022keV (two photons of 511keV each) is the energy given up to transition to the DDL state epo from the positronium atom. On Sun, Oct 25, 2015 at 12:19 PM, Eric Walker <eric.wal...@gmail.com> wrote: On Sun, Oct 25, 2015 at 12:56 PM, Bob Higgins <rj.bob.higg...@gmail.com> wrote: Regarding electrons and positrons in particular, Hotson rightly points out that these two particles are fermions. As fermions, they are forbidden to be in the same place at the same time, and so cannot annihilate. Instead of annihilation, they fall into orbit around each other. When (if) they reach a DDL orbit, the become a part of Dirac's negative energy sea. If positrons and electrons do not annihilate, where do the two oppositely-travelling 511 keV photons come from as a result of the activity of beta plus emitters? (Note that 511 keV is the mass of an electron or positron.) Eric
