In reply to  <[email protected]>'s message of Thu, 26 Jan 2017 08:24:35
-0800:
Hi Bob,
[snip]
>Robin—
>
>You note:  "Runaway" not possible, because the fuel isn't fissile anyway.  You 
>also say: 14 MeV neutrons are more than fast enough to fission Th (or any 
>Actinide for that matter, including U238) directly without
>conversion to a fissile isotope.  
>
>These two comments seem to contradict each other.
>
>Why can’t the 14 Mev neutrons cause a “Runaway”?
>
>Bob Cook

A runaway reaction is the result of a chain reaction, and fission reactions
create very few 14 MeV neutrons, not enough to cause a runaway reaction, which
incidentally is also the reason that U238 can't be used as reactor fuel in
normal reactors.

In the process I outlined, the 14 MeV neutrons would come from the fusion
process, and that in turn would depend on the muons to keep going, since the
operating temperature and pressure is too low by many orders of magnitude to
support a continuous fusion reaction.
Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html

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