Frederick Sparber wrote:
Posted earlier:
This Field Line Applet is cheaper than buying more VDGs.


http://www.cco.caltech.edu/~phys1/java/phys1/EField/EField.html

If the force around a positively charged sphere is reduced by
cladding it with a high dielectric constant material (K)

It won't be, not unless the cladding has a net charge. The dielectric or other properties of the cladding aren't relevant to its ability to "shield" something, which can be done only by canceling the original field. (There's no such thing as a "true" electric shield, of course. At least according to conventional theory, the E field obeys the law of superposition, and you can't actually "block" it; you can only cancel it.)

If you surround a charged sphere with any spherically symmetric material which does not, itself, carry a net charge, the result will be no change in the external field (outside the cladding) and no change in the net force acting on the system (sphere+cladding) due to an external field.


it's external force/field will drop off accordingly:
E = D/eo = D/(K*eo) = 1/K * 1/(4(pi) eo * Q/R^2

where D = 1/4(pi) * Q/R^2

Beware being mesmerized by the D field's behavior. Maxwell's equations are valid everywhere without any auxiliary fields (D and H) -- the aux fields are just a convenience, to make calculations easier inside matter where there are lots of mobile dipoles (both electric and magnetic), and to make the equations simpler in MKS units.

In electrostatics a sheet of high-dielectric insulator material immersed in a static E field perpendicular to its surface can be modeled as a capacitor: its dipoles align with the E field, all internal dipole "end fields" cancel, and the two surfaces of the insulator acquire charges, one positive and the other negative. Like any parallel plate capacitor, of course, the field outside the dielectric is (nearly) zero, and it's not going to have any effect on the external field of something around which it's wrapped.


Force = 1/K * 1/4(pi)eo * q* Q/R^2

Hence a 3-point craft with a cladded positive center sphere and
three exposed negative spheres should repel the earth's excess
negative charge up to an altitude that requires charge reversal for getting past the ionosphere.

That's just it.  It won't, if the cladding is neutral (no net charge).

If it did you could close the cladding, move a bit, open the cladding, move back, close the cladding, and so forth, and voila, you have a PMM. With uncharged cladding opening and closing the cladding (by sliding it) should require insignificant work.



http://www.cco.caltech.edu/~phys1/java/phys1/EField/EField.html

[Original Message]
From: Frederick Sparber <[EMAIL PROTECTED]>
To: <vortex-l@eskimo.com>
Date: 1/30/2007 4:51:38 AM
Subject: Re: [Vo]: Re: Re Van de Graaf Antics

Harry Veeder wrote
Fred,

Is your set-up capable of detecting either
an increase or a decrease in weight?

Yes Harry. It can be set on the Acculab 0-10 KG digital scale that
has a resolution of +/- 1.0 gram at any load up to 10 KG. The 200 KV VDG weighs 1.5 KG allowing for Styrofoam isolation for the scale and an inverter and a bank of 1.5 volt "D" batteries to
power
the scale and aluminum foil and the VDG so that charge can be
transferred
from the VDG and the aluminum foil which has about 6.0E*23 "uncommitted"
electrons per mole (27 grams).

If it wasn't for the cost I would use at least three VDGs for getting
a multipole field configuration to see how it interacts with the earth-ionosphere charges.

Fred
.
Harry








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