On May 29, 2007, at 2:17 PM, Robin van Spaandonk wrote:
In reply to Horace Heffner's message of Tue, 29 May 2007 12:28:49
-0800:
Hi,
[snip]
Regarding D + Pd cold fusion cathode conditions, Hora and Miley write
[1]: "The screened deuterons are mutually repulsed by their Coulomb
field at distances less than 2 pm, but thanks to their screening are
moving like neutral neutrons. Any attraction by the Casimir effect
[29] is too small. But calculating the gravitational attraction for
the deuteron masses at the 2 pm distance arrives at values of about
ten times higher energy than the thermal motion at room temperature.
[snip]
The gravitational energy between two deuterons at a distance of 2
pm is 2.3E-33
eV. This is about 1E31 times less than the kinetic energy at room
temperature.
Methinks the authors slipped more than one decimal.
Looking at the nucleon magnetic binding energy:
mu_n = nuclear magneton = 5.05078343(43)x 10^-27 A m^2
For deuterium, mu/mu_n = +0.8574382
For hydrogen, mu/mu_n = +2.7928474
Separation distance = 2 pm = 2E-12 m
Is interesting to see that a 50-50 mix of H and D would provide
maximal magnetic binding of the D through spin coupling.
The force F between two attractively aligned coils of magnetic
moments mu1 and mu2 at distance r is:
F = -3*mu0*(mu1)*(mu2)/(2*Pi*r^4)
so we can integrate to obtain the binding energy Fb:
Fb = mu0*(mu1)*(mu2)/(2*Pi*r^3)
which for deuterium is:
Fb = (1.2566E-6 N/A^2) * (0.8574*5.0508E-27 A m^2)^2 / (2*3.1416*
(2E-12 m)^3)
Fb = 4.688E-27 J = 2.93E-8 eV
which is way too low. However, if the nucleons can approach to 2E-14
m the magnetic biding energy rises to 0.0293 eV, which is right in
the ballpark of 0.038539 eV standard temperature energy.
It appears to me offhand the magnetic binding energy of the screening
electrons have to be brought into play to save the theory.
Regards,
Horace Heffner
