Horace, Your argument below is flawed because
E = grad (V) is the definition of V as much as it is the definition of E, so p1 and p2 cannot be fixed, as you imagined, independently of the real charges which determine the field: once you (the power supply) will have removed all N electrons from B1 and transferred them to B2, then the voltage difference will be as determined by the field created by the real charges. What would be idealized would be to imagine that a power supply can impose a given voltage difference across two bodies, regardless of the electrons those bodies can shed. Michel ----- Original Message ----- From: "Horace Heffner" <[EMAIL PROTECTED]> To: <vortex-l@eskimo.com> Sent: Saturday, August 11, 2007 2:17 AM Subject: Re: [Vo]:Re: Only potential differences matter (was Re: Deflation Fusion) ... > "The concepts you are applying are idealized. They > don't apply to reality without limits. If you have only two *real* > bodies B1 and B2 at potentials p1 and p2, body B1 having N electrons > and both B1 and B2 having M electrons, the field E at some point P > between them can not be maintained regardless the gauge. Once you > pick a gauge that requires B1 to be at a potential that requires it > to remove more than N electrons your formula > > E = grad (V) = grad (V+K) whatever the value of K > > no longer works. E is infeasible to maintain beyond certain bounds > on choice of gauge."
